Klu example problem:

Robertson kinetics, NEQ =  3


At t =   0.2636E+00   y =   0.989965E+00  0.347052E-04  0.100000E-01
     rootfound =   0  1
At t =   0.4000E+00   y =   0.985144E+00  0.338588E-04  0.148222E-01
At t =   0.4000E+01   y =   0.905426E+00  0.223942E-04  0.945515E-01
At t =   0.4000E+02   y =   0.715830E+00  0.918572E-05  0.284160E+00
At t =   0.4000E+03   y =   0.450560E+00  0.322342E-05  0.549437E+00
At t =   0.4000E+04   y =   0.183240E+00  0.894461E-06  0.816759E+00
At t =   0.4000E+05   y =   0.389806E-01  0.162165E-06  0.961019E+00
At t =   0.4000E+06   y =   0.493776E-02  0.198479E-07  0.995062E+00
At t =   0.4000E+07   y =   0.515949E-03  0.206485E-08  0.999484E+00
At t =   0.2082E+08   y =   0.100000E-03  0.400040E-09  0.999900E+00
     rootfound =  -1  0
At t =   0.4000E+08   y =   0.514789E-04  0.205926E-09  0.999949E+00
At t =   0.4000E+09   y =   0.542638E-05  0.217056E-10  0.999995E+00
At t =   0.4000E+10   y =   0.464797E-06  0.185919E-11  0.100000E+01
At t =   0.4000E+11   y =   0.486207E-07  0.194483E-12  0.100000E+01

Final value of ydot =  -0.876832E-18 -0.350733E-23  0.876835E-18


Final statistics:

 No. steps =  317    No. f-s =  941   No. J-s =   40    No. LU-s =  117
 No. nonlinear iterations =  940
 No. nonlinear convergence failures =    2
 No. error test failures =   11
 No. root function evals =  356
